4x^2-5x+19=0

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Solution for 4x^2-5x+19=0 equation:


Simplifying
4x2 + -5x + 19 = 0

Reorder the terms:
19 + -5x + 4x2 = 0

Solving
19 + -5x + 4x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
4 the coefficient of the squared term: 

Divide each side by '4'.
4.75 + -1.25x + x2 = 0

Move the constant term to the right:

Add '-4.75' to each side of the equation.
4.75 + -1.25x + -4.75 + x2 = 0 + -4.75

Reorder the terms:
4.75 + -4.75 + -1.25x + x2 = 0 + -4.75

Combine like terms: 4.75 + -4.75 = 0.00
0.00 + -1.25x + x2 = 0 + -4.75
-1.25x + x2 = 0 + -4.75

Combine like terms: 0 + -4.75 = -4.75
-1.25x + x2 = -4.75

The x term is -1.25x.  Take half its coefficient (-0.625).
Square it (0.390625) and add it to both sides.

Add '0.390625' to each side of the equation.
-1.25x + 0.390625 + x2 = -4.75 + 0.390625

Reorder the terms:
0.390625 + -1.25x + x2 = -4.75 + 0.390625

Combine like terms: -4.75 + 0.390625 = -4.359375
0.390625 + -1.25x + x2 = -4.359375

Factor a perfect square on the left side:
(x + -0.625)(x + -0.625) = -4.359375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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